Complex number arithmetic - cppreference.com (2024)

The C programming language, as of C99, supports complex number math with the three built-in types double _Complex, float _Complex, and long double _Complex (see _Complex). When the header <complex.h> is included, the three complex number types are also accessible as double complex, float complex, long double complex.

In addition to the complex types, the three imaginary types may be supported: double _Imaginary, float _Imaginary, and long double _Imaginary (see _Imaginary). When the header <complex.h> is included, the three imaginary types are also accessible as double imaginary, float imaginary, and long double imaginary.

Standard arithmetic operators +, -, *, / can be used with real, complex, and imaginary types in any combination.

Notes

The following function names are reserved for future addition to complex.h and are not available for use in the programs that include that header: cerf, cerfc, cexp2, cexpm1, clog10, clog1p, clog2, clgamma, and ctgamma, along with their -f and -l suffixed variants.

Although the C standard names the inverse hyperbolics with "complex arc hyperbolic sine" etc., the inverse functions of the hyperbolic functions are the area functions. Their argument is the area of a hyperbolic sector, not an arc. The correct names are "complex inverse hyperbolic sine" etc. Some authors use "complex area hyperbolic sine" etc.

A complex or imaginary number is infinite if one of its components is infinite, even if the other component is NaN.

A complex or imaginary number is finite if both components are neither infinities nor NaNs.

A complex or imaginary number is a zero if both components are positive or negative zeroes.

Example

#include <stdio.h>#include <complex.h>#include <tgmath.h>int main(void){ double complex z1 = I * I; // imaginary unit squared printf("I * I =%.1f%+.1fi\n", creal(z1), cimag(z1)); double complex z2 = pow(I, 2); // imaginary unit squared printf("pow(I, 2) =%.1f%+.1fi\n", creal(z2), cimag(z2)); double PI = acos(-1); double complex z3 = exp(I * PI); // Euler's formula printf("exp(I*PI) =%.1f%+.1fi\n", creal(z3), cimag(z3)); double complex z4 = 1+2*I, z5 = 1-2*I; // conjugates printf("(1+2i)*(1-2i) =%.1f%+.1fi\n", creal(z4*z5), cimag(z4*z5));}

I * I = -1.0+0.0ipow(I, 2) = -1.0+0.0iexp(I*PI) = -1.0+0.0i(1+2i)*(1-2i) = 5.0+0.0i

References